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-2x^2=-6x-140
We move all terms to the left:
-2x^2-(-6x-140)=0
We get rid of parentheses
-2x^2+6x+140=0
a = -2; b = 6; c = +140;
Δ = b2-4ac
Δ = 62-4·(-2)·140
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-34}{2*-2}=\frac{-40}{-4} =+10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+34}{2*-2}=\frac{28}{-4} =-7 $
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